Q:

C++ program to print all Even and Odd numbers from 1 to N

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 Take input from the user (N) and print all EVEN and ODD numbers between 1 to N.

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  • Input an integer number (N).
  • Run two separate loops from 1 to N.
  • In the first loop, check the condition to check EVEN numbers and print them.
  • In the second loop, check the condition to check ODD numbers and print them.
  • To check EVEN/ODD number – find the remainder dividing by 2, if it is 0 then the number will be an EVEN number, else the number will be an ODD number.

C++ program:

// C++ program to print all
// Even and Odd numbers from 1 to N

#include <iostream>
using namespace std;

// function : evenNumbers
// description: to print EVEN numbers only.
void evenNumbers(int n)
{
    int i;
    for (i = 1; i <= n; i++) {
        //condition to check EVEN numbers
        if (i % 2 == 0)
            cout << i << " ";
    }
    cout << "\n";
}

// function : oddNumbers
// description: to print ODD numbers only.
void oddNumbers(int n)
{
    int i;
    for (i = 1; i <= n; i++) {
        //condition to check ODD numbers
        if (i % 2 != 0)
            cout << i << " ";
    }
    cout << "\n";
}

// main code
int main()
{
    int N;
    // input the value of N
    cout << "Enter the value of N (limit): ";
    cin >> N;

    cout << "EVEN numbers are...\n";
    evenNumbers(N);

    cout << "ODD numbers are...\n";
    oddNumbers(N);

    return 0;
}

Output

 
RUN 1:
Enter the value of N (limit): 11
EVEN numbers are...
2 4 6 8 10
ODD numbers are...
1 3 5 7 9 11

RUN 2:
Enter the value of N (limit): 50
EVEN numbers are...
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50
ODD numbers are...
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49

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