C++ program to declare an integer variable dynamically and print its memory address

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2022-05-05

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C++ program to declare an integer variable dynamically and print its memory address

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mahmoud2506

2022-05-05

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Consider the following program:

#include <iostream>

using namespace std;

int main()
{
	//integer pointer declartion
	//It will contain the address of dynamically created 
	//memory blocks for an integer variable 
	int *ptr;
	
	//new will create memory blocks at run time 
	//for an integer variable
	ptr=new int;

	cout<<"Address of ptr: "<<(&ptr)<<endl;
	cout<<"Address that ptr contains: "<<ptr<<endl;

	//again assigning it run time
	ptr=new int;

	cout<<"Address of ptr: "<<(&ptr)<<endl;
	cout<<"Address that ptr contains: "<<ptr<<endl;

	//deallocating...
	delete (ptr);

	return 0;	
}

Output

    Address of ptr: 0x7ffebe87bb98
    Address that ptr contains: 0x2b31e4097c20
    Address of ptr: 0x7ffebe87bb98
    Address that ptr contains: 0x2b31e4098c50

Here we are declaring an integer pointer ptr and printing the address of ptr by using &ptr along with stored dynamically allocated memory block.

After that we are declaring memory for integer again and printing the same.

From this example - we can understand memory blocks are allocating dynamically, each time different memory blocks are storing in the pointer ptr.

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C++ program to declare an integer variable dynamically and print its memory address

C++ program to declare an integer variable dynamically and print its memory address

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