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Kasim Kamal Questions
290 Questions
Write a program to read the standard input a line at a time. Modify your program to read a word at a time
C++ programming
2022-07-03
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Rewrite the exercises from § 1.4.1 (p. 13) and § 2.6.2 (p. 76) with appropriate using declarations
C++ programming
2022-07-03
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We can use these facilities to guard against multiple inclusion as follows
C++ programming
2022-07-03
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Our other task is to check that the transactions are for the same ISBN. If so, we’ll print their sum, otherwise, we’ll print an error message
C++ programming
2022-07-03
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Our program will next repeat the same code to read data into data2
C++ programming
2022-07-03
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The string type holds a sequence of characters. Its operations include the >>, <<, and == operators to read, write, and compare strings, respectively. With this knowledge we can write the code to read the first transaction
C++ programming
2022-07-03
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Because this program will be longer than any we’ve written so far, we’ll explain it in separate parts. Overall, our program will have the following structure
C++ programming
2022-07-03
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The close curly that ends the class body must be followed by a semicolon. The semicolon is needed because we can define variables after the class body
C++ programming
2022-07-03
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We’ll name our version Sales_data to distinguish it from Sales_item. We’ll define our class as follows
C++ programming
2022-07-03
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Some expressions will cause decltype to yield a reference type. Generally speaking, decltype returns a reference type for expressions that yield objects that can stand on the left-hand side of the assignment
C++ programming
2022-07-03
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The way decltype handles top-level const and references differs subtly from the way auto does. When the expression to which we apply decltype is a variable, decltype returns the type of that variable, including top-level const and references
C++ programming
2022-07-03
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When we define several variables in the same statement, it is important to remember that a reference or pointer is part of a particular declarator and not part of the base type for the declaration. As usual, the initializers must provide consistent auto-deduced types
C++ programming
2022-07-03
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We can also specify that we want a reference to the auto-deduced type. Normal initialization rules still apply
C++ programming
2022-07-03
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290
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