The way decltype handles top-level const and references differs subtly from the way auto does. When the expression to which we apply decltype is a variable, decltype returns the type of that variable, including top-level const and references

belongs to book: C++ Primer|Stanley B.Lippman, Josee Lajoie, Barbara E.Moo|5th Edition| Chapter number:2| Question number:e.g2.5.3.1

KasimKamal

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2022-07-03

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The way decltype handles top-level const and references differs subtly from the way auto does. When the expression to which we apply decltype is a variable, decltype returns the type of that variable, including top-level const and references.

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KasimKamal

2022-07-03

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const int ci = 0, &cj = ci;
decltype(ci) x = 0; // x has type const int
decltype(cj) y = x; // y has type const int& and is bound to x
decltype(cj) z; // error: z is a reference and must be initialized

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The way decltype handles top-level const and references differs subtly from the way auto does. When the expression to which we apply decltype is a variable, decltype returns the type of that variable, including top-level const and references

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