Q:

Program to print the elements of an array present on even position

belongs to collection: Array Programs

robaa
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2022-11-09
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Explanation

In this program, we need to print the element which is present in even position.

Even positioned element can be found by traversing the array and incrementing the value of i by 2.

In the above array, elements on even position are b and d.

Algorithm

  1. Declare and initialize an array.
  2. Calculate the length of the declared array.
  3. Loop through the array by initializing the value of variable "i" to 1 (because first even positioned element lies on i = 1) then incrementing its value by 2, i.e., i=i+2.
  4. Print the elements present in even positions.

Input:

arr = [1, 2, 3, 4, 5]  

Output:

Elements of given array present on even position:
2
4
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All Answers

robaa
2022-11-09
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Python

#Initialize array   
arr = [1, 2, 3, 4, 5];   
   
print("Elements of given array present on even position: ");  
#Loop through the array by incrementing the value of i by 2  
  
#Here, i will start from 1 as first even positioned element is present at position 1.  
for i in range(1, len(arr), 2):  
    print(arr[i]);

 

Output:

Elements of given array present on even position: 
2
4

 

C

#include <stdio.h>  
   
int main()  
{  
    //Initialize array   
    int arr[] = {1, 2, 3, 4, 5};   
        //Calculate length of array arr  
    int length = sizeof(arr)/sizeof(arr[0]);  
    printf("Elements of given array present on even position: \n");  
    //Loop through the array by incrementing value of i by 2  
    //Here, i will start from 1 as first even positioned element is present at position 1.  
    for (int i = 1; i < length; i = i+2) {   
        printf("%d\n", arr[i]);   
    }   
    return 0;  
}

 

Output:

Elements of given array present on even position: 
2
4

 

JAVA

public class EvenPosition {  
    public static void main(String[] args) {  
          
        //Initialize array   
        int [] arr = new int [] {1, 2, 3, 4, 5};   
          
        System.out.println("Elements of given array present on even position: ");  
        //Loop through the array by incrementing value of i by 2  
        //Here, i will start from 1 as first even positioned element is present at position 1.  
        for (int i = 1; i < arr.length; i = i+2) {   
            System.out.println(arr[i]);   
        }    
    }  
}

 

Output:

Elements of given array present on even position: 
2
4

 

C#

using System;  
public class EvenPosition  
{  
    public static void Main()  
    {  
        //Initialize array   
        int [] arr = new int [] {1, 2, 3, 4, 5};   
          
        Console.WriteLine("Elements of given array present on even position: ");  
        //Loop through the array by incrementing value of i by 2  
        //Here, i will start from 1 as first even positioned element is present at position 1.  
        for (int i = 1; i < arr.Length; i = i+2) {   
            Console.WriteLine(arr[i]);   
        }    
    }  
}

 

Output:

Elements of given array present on even position: 
2
4

 

PHP

<!DOCTYPE html>  
<html>  
<body>  
<?php  
//Initialize array   
$arr = array(1, 2, 3, 4, 5);   
   
print("Elements of given array present on even position: <br>");  
//Loop through the array by incrementing value of i by 2  
//Here, i will start from 1 as first even positioned element is present at position 1.  
for ($i = 1; $i < count($arr); $i = $i+2) {   
    print($arr[$i] . "<br>");   
}    
?>  
</body>  
</html>

 

Output:

Elements of given array present on even position: 
2
4

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