Q:

Program to print the duplicate elements of an array

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robaa
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2022-11-08
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Explanation

In this program, we need to print the duplicate elements present in the array. This can be done through two loops. The first loop will select an element and the second loop will iteration through the array by comparing the selected element with other elements. If a match is found, print the duplicate element.

In the above array, the first duplicate will be found at the index 4 which is the duplicate of the element (2) present at index 1. So, duplicate elements in the above array are 2, 3 and 8.

Algorithm

  1. Declare and initialize an array.
  2. Duplicate elements can be found using two loops. The outer loop will iterate through the array from 0 to length of the array. The outer loop will select an element. The inner loop will be used to compare the selected element with the rest of the elements of the array.
  3. If a match is found which means the duplicate element is found then, display the element.

Input:

arr = [1, 2, 3, 4, 2, 7, 8, 8, 3];  

Output:

Duplicate elements in given array:
2
3
8
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All Answers

robaa
2022-11-08
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Python

#Initialize array   
arr = [1, 2, 3, 4, 2, 7, 8, 8, 3];   
   
print("Duplicate elements in given array: ");  
#Searches for duplicate element  
for i in range(0, len(arr)):  
    for j in range(i+1, len(arr)):  
        if(arr[i] == arr[j]):  
            print(arr[j]);

 

Output:

Duplicate elements in given array: 
2
3
8

 

C

#include <stdio.h>  
   
int main()  
{  
    //Initialize array   
    int arr[] = {1, 2, 3, 4, 2, 7, 8, 8, 3};   
      
    //Calculate length of array arr  
    int length = sizeof(arr)/sizeof(arr[0]);  
      
    printf("Duplicate elements in given array: \n");  
    //Searches for duplicate element  
    for(int i = 0; i < length; i++) {  
        for(int j = i + 1; j < length; j++) {  
            if(arr[i] == arr[j])  
                printf("%d\n", arr[j]);  
        }  
    }  
    return 0;  
}

 

Output:

Duplicate elements in given array: 
2
3
8

 

JAVA

public class DuplicateElement {  
    public static void main(String[] args) {      
          
        //Initialize array   
        int [] arr = new int [] {1, 2, 3, 4, 2, 7, 8, 8, 3};   
          
        System.out.println("Duplicate elements in given array: ");  
        //Searches for duplicate element  
        for(int i = 0; i < arr.length; i++) {  
            for(int j = i + 1; j < arr.length; j++) {  
                if(arr[i] == arr[j])  
                    System.out.println(arr[j]);  
            }  
        }  
    }  
}

 

Output:

Duplicate elements in given array: 
2
3
8

 

C#

using System;  
                      
public class DuplicateElement  
{  
    public static void Main()  
    {  
        //Initialize array   
        int [] arr = new int [] {1, 2, 3, 4, 2, 7, 8, 8, 3};   
          
       Console.WriteLine("Duplicate elements in given array: ");  
        //Searches for duplicate element  
        for(int i = 0; i < arr.Length; i++) {  
            for(int j = i + 1; j < arr.Length; j++) {  
                if(arr[i] == arr[j])  
                    Console.WriteLine(arr[j]);  
            }  
        }  
    }  
}

  

 

Output:

Duplicate elements in given array: 
2
3
8

 

PHP

<!DOCTYPE html>  
<html>  
<body>  
<?php  
//Initialize array   
$arr = array(1, 2, 3, 4, 2, 7, 8, 8, 3);   
   
print("Duplicate elements in given array: <br>");  
//Searches for duplicate element  
for($i = 0; $i < count($arr); $i++) {  
    for($j = $i + 1; $j < count($arr); $j++) {  
        if($arr[$i] == $arr[$j])  
            print($arr[$j] . "<br>");  
    }  
}  
?>  
</body>  
</html>

 

Output:

Duplicate elements in given array: 
2
3
8

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