Q:

Program to print the elements of an array in reverse order

belongs to collection: Array Programs

robaa
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2022-11-08
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Explanation

In this program, we need to print the elements of the array in reverse order that is; the last element should be displayed first, followed by second last element and so on.

Above array in reversed order:

Algorithm

  1. Declare and initialize an array.
  2. Loop through the array in reverse order that is, the loop will start from (length of the array - 1) and end at 0 by decreasing the value of i by 1.
  3. Print the element arr[i] in each iteration.

Input:

arr = [1, 2, 3, 4, 5]  

Output:

Original array: 1 2 3 4 5
Array in reverse order: 5 4 3 2 1
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All Answers

robaa
2022-11-08
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Python

#Initialize array   
arr = [1, 2, 3, 4, 5];   
print("Original array: ");  
for i in range(0, len(arr)):  
    print(arr[i]),   
print("Array in reverse order: ");  
#Loop through the array in reverse order  
for i in range(len(arr)-1, -1, -1):   
    print(arr[i]),

 

Output:

Original array: 
1 2 3 4 5 
Array in reverse order: 
5 4 3 2 1

 

C

#include <stdio.h>  
   
int main()  
{  
    //Initialize array   
    int arr[] = {1, 2, 3, 4, 5};   
      
    //Calculate length of array arr  
    int length = sizeof(arr)/sizeof(arr[0]);  
      
    printf("Original array: \n");  
    for (int i = 0; i < length; i++) {   
        printf("%d ", arr[i]);   
    }    
      
    printf("\n");  
      
    printf("Array in reverse order: \n");  
    //Loop through the array in reverse order  
    for (int i = length-1; i >= 0; i--) {   
        printf("%d ", arr[i]);   
    }   
    return 0;  
}

 

Output:

Original array: 
1 2 3 4 5 
Array in reverse order: 
5 4 3 2 1

 

JAVA

public class ReverseArray {  
    public static void main(String[] args) {      
          
        //Initialize array   
        int [] arr = new int [] {1, 2, 3, 4, 5};   
          
        System.out.println("Original array: ");  
        for (int i = 0; i < arr.length; i++) {   
            System.out.print(arr[i] + " ");   
        }    
          
        System.out.println();  
          
        System.out.println("Array in reverse order: ");  
        //Loop through the array in reverse order  
        for (int i = arr.length-1; i >= 0; i--) {   
            System.out.print(arr[i] + " ");   
        }    
    }  
}

 

Output:

Original array: 
1 2 3 4 5 
Array in reverse order: 
5 4 3 2 1

 

C#

using System;  
                      
public class ReverseArray  
{  
    public static void Main()  
    {  
        //Initialize array   
        int [] arr = new int [] {1, 2, 3, 4, 5};   
          
        Console.WriteLine("Original array: ");  
        for (int i = 0; i < arr.Length; i++) {   
            Console.Write(arr[i] + " ");   
        }    
          
        Console.WriteLine();  
          
        Console.WriteLine("Array in reverse order: ");  
        //Loop through the array in reverse order  
        for (int i = arr.Length-1; i >= 0; i--) {   
            Console.Write(arr[i] + " ");   
        }    
    }  
}

 

 

Output:

Original array: 
1 2 3 4 5 
Array in reverse order: 
5 4 3 2 1

 

PHP

<!DOCTYPE html>  
<html>  
<body>  
<?php  
//Initialize array   
$arr = array(1, 2, 3, 4, 5);   
   
print("Original array: <br>");  
for ($i = 0; $i < count($arr); $i++) {   
    print($arr[$i] . " ");   
}    
   
print("<br>");  
   
print("Array in reverse order: <br>");  
//Loop through the array in reverse order  
for ($i = count($arr)-1; $i >= 0; $i--) {   
    print($arr[$i] . " "); ;   
}      
?>  
</body>  
</html>

 

Output:

Original array: 
1 2 3 4 5 
Array in reverse order: 
5 4 3 2 1

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