Find the output of C#.Net programs | Arrays | Set 1: Enhance the knowledge of C#.Net Arrays concepts by solving and finding the output of some C#.Net programs.
Question 1:
using System;
namespace Demo
{
class Program
{
//Entry point of the program
static void Main(string[] args)
{
int arr[]={1,2,3,4,5};
for(int i=0; i<5;i++)
{
Console.WriteLine(arr[i]);
}
}
}
}
Question 2:
using System;
namespace Demo
{
class Program
{
//Entry point of the program
static void Main(string[] args)
{
int []arr;
int ok = 0;
arr = new int[5];
arr[0] = 32;
arr[1] = 16;
arr[2] = 48;
arr[3] = 25;
arr[4] = 67;
ok = arr[0];
for(int i=1; i<arr.Size();i++)
{
if (ok > arr[i])
ok = arr[i];
}
Console.WriteLine(ok);
}
}
}
Question 3:
using System;
namespace Demo
{
class Program
{
//Entry point of the program
static void Main(string[] args)
{
int []arr;
int ok = 0;
arr = new int[5];
arr[0] = 32;
arr[1] = 16;
arr[2] = 48;
arr[3] = 25;
arr[4] = 67;
ok = arr[0];
for(int i=1; i<arr.Length;i++)
{
if (ok > arr[i])
ok = arr[i];
}
Console.WriteLine(ok);
}
}
}
Question 4:
using System;
namespace Demo
{
class Program
{
//Entry point of the program
static void Main(string[] args)
{
int []arr;
int ok = 0;
arr = new int[5];
arr[0] = 32;
arr[1] = 16;
arr[2] = 48;
arr[3] = 25;
arr[4] = 67;
ok = arr[0];
for(int i=1; i<arr.Length;i++)
{
if (ok > Convert.ToInt32(arr.GetValue(i)))
ok = arr[i];
}
Console.WriteLine(ok);
}
}
}
Question 5:
using System;
namespace Demo
{
class Program
{
//Entry point of the program
static void Main(string[] args)
{
int []arr={1,7};
arr = new int[5];
for (int I = 0; I < 5; I++)
{
Console.WriteLine(5*arr[I]);
}
}
}
}
c# programming
Answer 1:
Output:
Explanation:
The above program will generate syntax errors. Because we used incorrect syntax for array declaration.
The correct syntax is given below:
int []arr={1,2,3,4,5};Answer 2:
Output:
Explanation:
The above program will generate syntax error because Size() is not an inbuilt method in C#.
The Length property is used to get the length of an array in C#.
Answer 3:
Output:
Explanation:
In the above program, we declared an integer array arr with size 5, and declared a local variable ok.
Here, we used Length property that will return 5, so the loop will execute until the value of the variable i is less than 5.
In the above statement, we assigned the first value of an array to the variable ok.
Let's iterate the loop step by step,
Iteration1: ok=32, i=1 Here we check condition 32>16, then assign 16 to the variable “ok”. Iteration2: ok=16, i=2 Here we check condition 16>48, the condition is false. Then value "ok" will not change. Iteration3: ok=16, i=3 Here we check condition 16>25, the condition is false. Then value "ok" will not change. Iteration4: ok=16, i=4 Here we check condition 16>67, the condition is false. Then value "ok" will not change.Now the value of 'i' will 5, and loop condition will false and the loop will terminate. And "16" will be printed on the console screen.
Answer 4:
Output:
Explanation:
In the above program, we declared an integer array arr with size 5, and declared a local variable ok.
Here, we used Length property that will return 5, so the loop will execute until the value of the variable i is less than 5.
ok = arr[0];In the above statement, we assigned the first value of an array to the variable ok.
Convert.ToInt32(arr.GetValue(i))In the above program, we used the GetValue() method, this method is used to get elements of the array,
Based on the index, but this method return value of object type, that's why here we converted returned value into a 32-bit integer.
Let's iterate the loop step by step,
Iteration1: ok=32, i=1 Here we check condition 32>16, then assign 16 to the variable “ok”. Iteration2: ok=16, i=2 Here we check condition 16>48, the condition is false. Then value "ok" will not change. Iteration3: ok=16, i=3 Here we check condition 16>25, the condition is false. Then value "ok" will not change. Iteration4: ok=16, i=4 Here we check condition 16>67, the condition is false. Then value "ok" will not change.Now the value of 'i' will 5, and loop condition will false and the loop will terminate. And "16" will be printed on the console screen.
Answer 5:
Output:
Explanation:
In the above program, we created an integer array initialized with 2 elements {1,7}. But after that, we reallocate space for array arr with 5 elements using new operator. That's why all 5 elements will be '0'.
In the loop body, we used the WriteLine() method that will print 0 in every iteration, because multiplication 5 with 0 will be 0. All elements of the array are 0.
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