Explanation
In this program, we will create a doubly linked list then, iterate through the list to find out the minimum and maximum node.
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We will maintain two variables min and max. Min will hold the minimum value node, and max will hold the maximum value node. In above example, 1 will be the minimum value node and 9 will be the maximum value node.
Algorithm
- Define a Node class which represents a node in the list. It will have three properties: data, previous which will point to the previous node and next which will point to the next node.
- Define another class for creating the doubly linked list, and it has two nodes: head and tail. Initially, head and tail will point to null.
- minimumNode() will prints out minimum value node:
- Define variable min and initialize with head's data.
- Current will point to head.
- Iterate through the list by comparing each node's data with min.
- If min > current's data then min will hold current's data.
- At the end of the list, variable min will hold the minimum value node.
- Print the min value.
- maximumNode() will prints out maximum value node:
- Define variable max and initialize with head's data.
- Current will point to head.
- Iterate through the list by comparing each node's data with max.
- If max < current's data then max will hold current?s data.
- At the end of the list, variable max will hold the maximum value node.
- Print the max value.
Input:
#Add nodes to the list
dList.addNode(5);
dList.addNode(7);
dList.addNode(9);
dList.addNode(1);
dList.addNode(2);
Output:
Minimum value node in the list: 1
Maximum value node in the list: 9
Python
Output:
C
Output:
JAVA
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C#
Output:
PHP
Output: