Q:

Program to print the combination (nCr) of the given number

belongs to collection: Number Programs

robaa
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2022-11-09
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Combination (nCr) can be defined as the combination of n things taken r at a time without any repetition.

ncr can be calculated as,

 

nCr = [n(n-1) ... (n-r+1)] / r(r-1)...1  

Algorithm

MAIN

  • STEP 1: START
  • STEP 2: DEFINE n, r
  • STEP 3: ENTER n, r
  • STEP 4: PRINT nCr(n, r)
  • STEP 5: END

nCr(n r)

  • STEP 1: START
  • STEP 2: RETURN fact(n) / (fact(r)*fact (n-r))
  • STEP 3: END

fact(n)

  • STEP 1: START
  • STEP 2: SET res= 1
  • STEP 3: REPEAT STEP 3 and STEP 4 UNTIL i<=n
  • STEP 4: res = res*i
  • STEP 5: RETURN res
  • STEP 6: END
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All Answers

robaa
2022-11-09
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Java Program

import java.util.*;  
class Combination {   
static int nCr(int n, int r)   
{   
    return fact(n) / (fact(r) *   
    fact(n - r));   
}   
static int fact(int n)   
{   
    int res = 1;   
           for (int i = 2; i <= n; i++)   
           res = res * i;   
          return res;   
}   
public static void main(String[] args)   
{   
int n,r;  
System.out.println("Enter the value of n and r?");  
Scanner sc = new Scanner(System.in);  
n = sc.nextInt();  
r = sc.nextInt();  
System.out.println("nCr = "+nCr(n, r));  
}   
}

 

Output:

Enter the value of n and r?
6
4
nCr = 15

 

C Program

#include <stdio.h>  
int fact(int z);  
void main()  
{  
    int n, r, nCr;  
    printf("Enter the value of n and r?");  
    scanf("%d %d",&n,&r);  
    nCr = fact(n) / (fact(r) * fact(n - r));  
    printf("\nnCr = %d", nCr);  
}  
  
int fact(int z)  
{  
    int f = 1, i;  
    if (z == 0)  
    {  
        return(f);  
    }  
    else  
    {  
        for (i = 1; i <= z; i++)  
    {  
            f = f * i;  
    }  
    }  
    return(f);  
}

 

Output:

Enter the value of n and r? 5  3
nCr = 10

 

Python Program

def fact(z):  
    f = 1  
    if z == 0:  
        return f;  
    else:  
        for i in range(1,z+1):  
            f = f * i;  
        return f;  
  
  
n=int(input("Enter the value of n"))  
r = int(input("Enter the value of r"))  
nCr = fact(n) / (fact(r) * fact(n - r));  
print("\nnCr = %d" %(nCr));

 

Output:

Enter the value of n 5
Enter the value of r 3
nCr = 10

 

C# Program

using System;   
class Combination  
{  
static int nCr(int n, int r)   
{   
   return fact(n) / (fact(r) *   
     fact(n - r));   
}   
  static int fact(int n)   
{   
  int res = 1;   
  for (int i = 2; i <= n; i++)   
   res = res * i;   
  return res;   
}   
   public static void Main()   
 {   
   int n,r;  
   Console.WriteLine("Enter the value of n and r?");  
   n = Convert.ToInt32(Console.ReadLine());  
   r = Convert.ToInt32(Console.ReadLine());  
   Console.Write("nCr = "+nCr(n, r));   
 }   
}

 

Output:

Enter the value of n and r? 5 3  
nCr = 10

 

PHP Program

<?php   
function nCr( $n, $r)   
{   
  return fact($n) / (fact($r) *  fact($n - $r));   
}   
function fact( $n)   
{   
 $res = 1;   
  for ( $i = 2; $i <= $n; $i++)   
  $res = $res * $i;   
  return $res;   
}   
 echo "Enter the value of n and r?";  
 $n = readline();   
 $r = readline();   
  echo "ncr = ";  
  echo nCr($n, $r);   
?>

 

Output:

Enter the value of n and r? 5 3  
nCr = 10

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