Program to print the average of n numbers

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robaa

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2022-11-09

151

The average is the outcome from the sum of the numbers divided by the count of the numbers being averaged.

For example: 1,2,3,4,5

Number of all elements = 5

Sum of all elements = 1+2+3+4+5 =15

Average = Sum of all elements / number of all elements = 15/5 =3

Average =3

Algorithm

STEP 1: START
STEP 2: DEFINE n.
STEP 3: SET count = 1
STEP 4: DEFINE xF, averageF
STEP 5: SET sumF = 0
STEP 6: ENTER n
STEP 7: REPEAT STEP 8 to 10 UNTIL count<=n
STEP 8: Enter xF
STEP 9: sumF += xF
SETP 10: count = count + 1
SETP 11: SET averageF = sumF/(n-1)
STEP 12: PRINT averageF
STEP 13: END

All Answers

robaa

2022-11-09

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Java Program

import static java.lang.Float.sum;  
import java.util.Scanner;  
public class Average {  
   public static void main(String[] args)  
    {  
      int n, count = 1;   
      float  xF, averageF, sumF = 0;   
      Scanner sc = new Scanner(System.in);     
      System.out.println("Enter the value of n");  
      n = sc.nextInt();  
      while (count <= n)   
             {   
                  System.out.println("Enter the "+count+" number?");  
                  xF = sc.nextInt();  
                  sumF += xF;   
                  ++count;   
             }   
                  averageF = sumF/n;   
        System.out.println("The Average is"+averageF);  
    }    
}

Output:

Enter the value of n
5
Enter the 1 number?
1
Enter the 2 number?
2  
Enter the 3 number?
3
Enter the 4 number?
4
Enter the 5 number?
5
The Average is 3.0

C program

#include<stdio.h>  
void main( )   
{   
  int n, count = 1;   
  float x, average, sum = 0;   
  printf("Enter the value of n?");  
  scanf ("%d",&n);   
  while (count <= n)   
     {   
      printf ("Enter the %d number?",count);   
      scanf("%f", &x);   
      sum += x;   
      ++count;   
     }   
      average = sum/n;   
      printf("\nThe Average is %f\n", average);   
}

Output:

Enter the value of n? 5
Enter the 1 number? 1
Enter the 2 number? 2
Enter the 3 number? 3
Enter the 4 number? 4
Enter the 5 number? 5

The Average is 3.0000

Python program

n = int(input("Enter the value of n?"))  
sum=0  
count = 1  
while (count<=n):  
    x = int(input("Enter the %d number?"%(count)));  
    sum = sum + x;  
    count=count+1;  
average  = sum / n;  
print("Average using a while loop ", average)

Output:

Enter the value of n? 5
Enter the 1 number? 1
Enter the 2 number? 2
Enter the 3 number? 3
Enter the 4 number? 4
Enter the 5 number? 5
Average using a while loop   3.0000

Php program

<?php  
$count=1;  
$sum = 0;  
$average=0;  
echo "Enter the value of n?";  
$n = readline();  
while($count<=$n)  
{  
echo "Enter the number";  
$x = readline();  
$sum = $sum+$x;  
$count=$count+1;  
}  
$average=$sum/$n;  
echo $average;  
?>

Output:

Enter the value of n? 5
Enter the number 1
Enter the number 2
Enter the number 3
Enter the number 4
Enter the number 5
3.0000

C# program

using System;   
public class Average  
{  
   public static void Main()  
    {  
       int userInput;  
       int  n, count = 1;   
      float  x, average, sum = 0;   
      Console.WriteLine("Enter the value of n?");  
      n=Convert.ToInt32(Console.ReadLine());  
      while (count <= n)   
             {   
                  Console.WriteLine("Enter the "+count+" number?" );   
                  userInput = Convert.ToInt32(Console.ReadLine());  
                  sum += userInput;   
                  ++count;  
             }   
                  average = (float)sum/(n);   
                  Console.WriteLine("\nThe Average is %f\n");  
       Console.Write(average);       
}}

Output:

Enter the value of n?
5
Enter the 1 number?
1
Enter the 2 number?
2  
Enter the 3 number?
3
Enter the 4 number?
4
Enter the 5 number?
5
The Average is 3.0

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