Q:

C++ Class and Objects | Find output programs | Set 4

belongs to collection: C++ find output programs

robaa

Save to bookmark

|

2022-11-21

|

184

0

This section contains the C++ find output programs with their explanations on C++ Class and Objects (set 4).

Program 1:

#include <iostream>
using namespace std;

class Sample {
    int X;
    int* const PTR = &X;

public:
    void set(int x);
    void print();
};

void Sample::set(int x)
{
    *PTR = x;
}

void Sample::print()
{
    cout << *PTR - EOF << " ";
}

int main()
{
    Sample S;

    S.set(10);
    S.print();

    return 0;
}

Program 2:

#include <iostream>
using namespace std;

class Sample {
    int X;
    int* const PTR = &X;

public:
    void set(int x);
    void print();
};

void Sample::set(int x)
{
    *PTR = x;
}

void Sample::print()
{
    cout << *PTR - EOF << " ";
}

int main()
{
    Sample* S;

    S->set(10);
    S->print();

    return 0;
}

Program 3:

#include <iostream>
using namespace std;

class Sample {
    int X;
    int* const PTR = &X;

public:
    void set(int x);
    void print();
};

void Sample::set(int x)
{
    *PTR = x;
}

void Sample::print()
{
    cout << *PTR - EOF << " ";
}

int main()
{
    Sample* S = &(Sample());

    S->set(10);
    S->print();

    return 0;
}

C++ programming, examples, C++ programming examples,

login and add your own answer to this question

All Answers

robaa

2022-11-21

need an explanation for this answer? contact us directly to get an explanation for this answer

Answer Program 1:

Output:

Explanation:

In the above program, we created class Sample that contain member X and a constant pointer PTR that contains the address of X, here we cannot relocate the pointer but we can change the value of X using pointer PTR.

Here, we defined two member functions set() and print() outside the class.

The set() function set the value to the data member X. and print() member function uses cout statement.

cout << *PTR-EOF << " ";

The value of EOF is -1 then 10- -1 = 11.

Thus, 11 will be printed on the console screen.

Answer Program 2:

Output:

Segmentation fault (core dumped)
OR
Runtime error

Explanation:

The above code will generate a runtime error because in the above program we created the pointer of the class but, we did not initialize pointer PTR with any object of the Sample class. If we try to access the member of the class Sample then it will generate a runtime error.

Answer Program 3:

Output:

main.cpp: In function ‘int main()’:
main.cpp:25:27: error: taking address of temporary [-fpermissive]
     Sample* S = &(Sample());
                           ^

Explanation:

The above program will generate an error due to the below statement used in the main() function:

Sample *S = &(Sample());

Here we created a pointer of the class and tried to initialize with the object of the class, this is not the correct way. The correct way is,

Sample OB;
Sample *S = &OB;

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)

C++ Class and Objects | Find output programs | Set... >>

<< C++ Class and Objects | Find output programs | Set...