Java program to check whether the number is IMEI Number or not

belongs to collection: Java Basic Programs

mahmoud2506

Save to bookmark

2022-05-06

279

Given a number, we have to check that the entered number is IMEI Number or not.

An IMEI number is a 15 digit number and it is said to be IMEI number if and only if the sum of the number is exactly divisible by 10. But the condition is that when we entered the number the digit next to the previous one is taken as its double.

Example:

    Input: 47415403237518

    Output:
    47415403237518 – Is an IMEI Number.

Java programming, exam questions, Java programming exam-questions,

All Answers

mahmoud2506

2022-05-06

need an explanation for this answer? contact us directly to get an explanation for this answer

Program to check valid IMEI number in java

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class CheckIMEINumber
{
	// Function for finding and returning sum of digits of a number
	int sumDig(int n) 
	{
		// initialise here.
		int a = 0;
	    while(n>0)
	    {
	    	a = a + n%10;
	        n = n/10;
	    }
	    return a;
	}
	     
	public static void main(String args[])throws IOException
	{
		// create object here.
		CheckIMEINumber ob = new CheckIMEINumber();
	    BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
	         
	    // The 'Long' data type is used to store 15 digits.
	    System.out.print("Enter a 15 digit IMEI code : ");
	    long n = Long.parseLong(br.readLine()); 
	         
	    // Converting the number into String for finding length
	    String s = Long.toString(n); 
	    int l = s.length();
	    
	    // If length is not 15 then IMEI is Invalid
	    if(l!=15) 
	    System.out.println("Output : Invalid Input");
	    
	    else
	    {
	    	int d = 0, sum = 0;
	        for(int i=15; i>=1; i--)
	        {
	        	d = (int)(n%10);
	                 
	        	if(i%2 == 0)
	            {
	        		// Doubling every alternate digit
	        		d = 2*d; 
	            }
	 
	        	// Finding sum of the digits
	        	sum = sum + ob.sumDig(d); 
	        	n = n/10;
	        }
	             
	        System.out.println("Output : Sum = "+sum);
	        
	        if(sum%10==0)    
	        	System.out.println("Valid IMEI Code");
	        else
	            System.out.println("Invalid IMEI Code");
	    }
	}
}

Output

First run:
Enter a 15 digit IMEI code : 111111111111111
Output : Sum = 22
Invalid IMEI Code

Second run:
Enter a 15 digit IMEI code : 474154203237518
Output : Sum = 60
Valid IMEI Code

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)