Q:

Java program to divide two numbers and catch the exception, if divisor is 0

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mahmoud2506
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2022-05-06
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Given two integer numbers and we have to divide them by checking exception if divisor is 0.

Example:

    Input:
    Enter first number : 70
    Enter second number : 5

    Output:
    Result:14 
    Explanation: There is no exception because divisor is not 0

    Input:
    Enter first number : 100
    Enter second number : 0

    Output:
    Error:/ by zero

    Explanation: Error:java.lang.ArithmeticException: / by zero

 

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mahmoud2506
2022-05-06
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Java program:

package ExceptionHandling;

import java.util.Scanner;

class Ex1
{  
	public static void main(String arg[])
    {  
		try
		{
			// declare and initialize here.
			int a,b,c;
			Scanner KB=new Scanner(System.in);
			
			// input numbers here.
			System.out.print("Enter first number : ");
			a=KB.nextInt();
       
			System.out.print("Enter second number : ");
			b=KB.nextInt();
       
			//throw to catch
			c=a/b;
			System.out.println("Result:"+c);
		}
		catch(ArithmeticException e)
		{
			System.out.println("Error:"+e.getMessage());
			System.out.println("Error:"+e);
		}
		// here program ends.
		System.out.println("End of Program...");
	}
}

Output

First run:
Enter first number : 100
Enter second number : 0
Error:/ by zero
Error:java.lang.ArithmeticException: / by zero
End of Program...

Second run:
Enter first number : 70
Enter second number : 5
Result:14
End of Program...

 

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