Q:

Java program to check Emrip number

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mahmoud2506
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2022-05-06
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Given an integer number and we have to check whether it is Emrip number or not using Java program.

Example:

 

    Input: 13
    Output:
    13 is Emrip number
    Explanation:
    13 and its reverse is 31 both are primer numbers

 

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mahmoud2506
2022-05-06
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Program to check Emrip number in java

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

class CheckEmirpNumber
{
	// create object and intialize here.
	static BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
	int n, rev, f;

	// create parameterised constructor
	CheckEmirpNumber(int nn) 
	{
		n=nn;
		rev=0;
		f=2;
	}

	// function for checking the prime number.
	int isprime(int x) 
	{
		if(f<=x)
		{
			if(x%f!=0) 
			{
				f++;
				isprime(x);
			}
		}

		if(f==x)
			return 1;
		else
			return 0;
	}

	// function to check Emrip number.
	void isEmirp()
	{
		int copy=n, d;
		
		// reversing the number.
		while(copy>0) 
		{
			d=copy%10;
			rev=rev*10+d;
			copy=copy/10;
		}
		
		
		int a=isprime(n); 
		f=2; 
		int b=isprime(rev); 
		
		// if both a and b are equal then it is Emrip
		if(a==1 && b==1)
			System.out.println(n+" is an Emirp Number");
		else
			System.out.println(n+" is Not an Emirp Number");
	}

	public static void main(String args[])throws IOException
	{
		// Enter the number
		System.out.print("Enter the number : ");
		
		int n=Integer.parseInt(br.readLine());
		
		// call the function to check.
		CheckEmirpNumber ob=new CheckEmirpNumber(n);
		ob.isEmirp();
	}    
}

Output

First run:
Enter any number : 13
13 is an Emirp Number

Second run:
Enter the number : 250
250 is Not an Emirp Number

 

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