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What is the output of the below C code?

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YasminRadwan26

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2022-06-24

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What is the output of the below C code?

#include <stdio.h>
int main()
{
    int pos = 14;
    float data = 15.2;
    printf("%*f",pos,data);
    return 0;
}

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YasminRadwan26

2022-06-24

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Output:

print 15.200000 with 6 spaces.

Explanation: The output will be ______15.20000, where _ has been used to represent space here. The program will print a floating-point number with a width of at least 14 and since no precision has been specified, it will take the default precision of 6 decimal point for format specifier “f”.

The symbol * can be used with a format specifier to replace the width or precision. Here it has been used to replace the width. The general format for %f can be seen as %(width). (precision)f. When * is used to specify width or precision. Let see a C code for the same.

#include <stdio.h>
int main()
{
    int pos = 14;
    float data = 15.2;
    printf("%*.*f",pos,2,data);
    return 0;
}

Output:

print 15.20 with spaces.

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