Q:

Python | Program to remove duplicate elements from the list

belongs to collection: Python List Programs

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Example:

    Input:
    list1:  [10, 20, 10, 20, 30, 40, 30, 50]

    Output:
    List after removing duplicate elements
    list2:  [10, 20, 30, 40, 50]

Logic:

To implement the program is too easy, we have to append elements one by one to another list by checking whether element is available in the new list or not.

Let suppose, 20 is available three times in the list list1 and when we append 20 (first occurrence) to the list list2, it will be appended, but when we append 20 (second occurrence) to the list list2, condition will be false and item will not be appended. And finally, we will get list without duplicate elements.

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Program:

# declare list 
list1 = [10, 20, 10, 20, 30, 40, 30, 50]

# creating another list with unique elements
# declare another list 
list2 = []

# appending elements 
for n in list1:
	if n not in list2:
		list2.append(n)

# printing the lists 
print "Original list"
print "list1: ", list1
print "List after removing duplicate elements"
print "list2: ", list2

Output

    Original list
    list1:  [10, 20, 10, 20, 30, 40, 30, 50]
    List after removing duplicate elements
    list2:  [10, 20, 30, 40, 50]

Program (Defining User defines function):

# Function to remove duplicates 
def removeDuplicates (list1):
	# declare another list
	list2 = []

	# appending elements 
	for n in list1:
		if n not in list2:
			list2.append (n)
	return list2

# Main code
# declare a list
list1 = [10, 20, 10, 20, 30, 40, 30, 50]
# print the list 
print "Original list: ", list1
print "List after duplicate remove: ", removeDuplicates (list1)

Output

    Original list:  [10, 20, 10, 20, 30, 40, 30, 50]
    List after duplicate remove:  [10, 20, 30, 40, 50]

 

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