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Python | Program to find the differences of two lists

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mahmoud2506
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2022-05-22
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Given two lists of integers, we have to find the differences i.e. the elements which are not exists in second lists.

Example:

    Input:
    List1 = [10, 20, 30, 40, 50]
    List2 = [10, 20, 30, 60, 70]

    Output:
    Different elements:
    [40, 50]

Logic:

To find the differences of the lists, we are using set() Method, in this way, we have to explicitly convert lists into sets and then subtract the set converted lists, the result will be the elements which are not exist in the second.

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mahmoud2506
2022-05-22
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Program to find difference of two lists in Python

# list1 - first list of the integers
# lists2 - second list of the integers
list1 = [10, 20, 30, 40, 50]
list2 = [10, 20, 30, 60, 70]

# printing lists 
print "list1:", list1
print "list2:", list2

# finding and printing differences of the lists
print "Difference elements:"
print (list (set(list1) - set (list2)))

Output

    list1: [10, 20, 30, 40, 50]
    list2: [10, 20, 30, 60, 70]
    Difference elements:
    [40, 50]

Program 2: with mixed type of elements, printing 1) the elements which are not exist in list2 and 2) the elements which are not exists in list1.

# list1 - first list with mixed type elements
# lists2 - second list with mixed type elements
list1 = ["Amit", "Shukla", 21, "New Delhi"]
list2 = ["Aman", "Shukla", 21, "Mumbai"]

# printing lists 
print "list1:", list1
print "list2:", list2

# finding and printing differences of the lists
print "Elements not exists in list2:"
print (list (set(list1) - set (list2)))

print "Elements not exists in list1:"
print (list (set(list2) - set (list1)))

Output

    list1: ['Amit', 'Shukla', 21, 'New Delhi']
    list2: ['Aman', 'Shukla', 21, 'Mumbai']
    Elements not exists in list2:
    ['Amit', 'New Delhi']
    Elements not exists in list1:
    ['Aman', 'Mumbai']

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