Q:

Error: missing terminating double quote character in C

belongs to collection: C Common Errors Programs

mahmoud2506
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2022-05-04
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Error: missing terminating double quote character in C

This Error: missing terminating (") character is occurred, when a constant string or text is not closed in double quotes either you missed closing quotes or using singe quote instead of double quote while closing the string/text.

If string/text is not closed in double quotes, compiler throws this error.

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mahmoud2506
2022-05-04
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Example 1:

#include <stdio.h>

int main(void) {
    
	//closing double quote is missing 
	printf("Hello world);

	return 0;
}

Output

prog.c: In function ‘main’:
prog.c:6:9: warning: missing terminating " character
  printf("Hello world);
         ^
prog.c:6:9: error: missing terminating " character
  printf("Hello world);
         ^~~~~~~~~~~~~~
prog.c:8:2: error: expected expression before ‘return’
  return 0;
  ^~~~~~
prog.c:9:1: error: expected ‘;’ before ‘}’ token
 }
 ^

Example 2:

#include <stdio.h>

int main(void) {
    
	//closing double quote is missing 
	printf("Hello world');

	return 0;
}

Output

prog.c: In function ‘main’:
prog.c:6:9: warning: missing terminating " character
  printf("Hello world');
         ^
prog.c:6:9: error: missing terminating " character
  printf("Hello world');
         ^~~~~~~~~~~~~~~
prog.c:8:2: error: expected expression before ‘return’
  return 0;
  ^~~~~~
prog.c:9:1: error: expected ‘;’ before ‘}’ token
 }
 ^

How to fix?

In the first program, closing double quote is missing, and in the second program, text is closing by single quote instead of double quote.

To fix this error, use double quote to close the string/text.

Correct code:

#include <stdio.h>

int main(void) {
    
	//closing double quote is missing 
	printf("Hello world");

	return 0;
}

Output

Hello world

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