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C program to print alternate elements of the array
Q:

C program to print alternate elements of the array

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C program to print alternate elements of the array

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Here, we will create an array of integers then print alternate elements of an array on the console screen.

Program:

The source code to print alternate elements of the array is given below. The given program is compiled and executed using GCC compile on UBUNTU 18.04 OS successfully.

// C program to print alternate elements of array.

#include <stdio.h>

int main()
{
    int arr[] = { 10, 20, 30, 40, 50, 60, 70, 80, 90, 10 };
    int i = 0;

    printf("Alternate elements of array: ");
    for (i = 0; i < 10; i = i + 2)
        printf("\n\tarr[%d] is: %d", i, arr[i]);

    printf("\n");
    return 0;
}

Output:

Alternate elements of array: 
	arr[0] is: 10
	arr[2] is: 30
	arr[4] is: 50
	arr[6] is: 70
	arr[8] is: 90

Explanation:

Here, we created an array arr with 10 elements, and then we increased the value of the counter variable i by 2 in the for loop to print alternate elements of an array on the console screen.

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