Q:

# C program to print EVEN numbers from 1 to N using while loop

Given a range (value of N) and we have to print all EVEN numbers from 1 to N using while loop.

Example:

```    Input:
Enter value of N: 10

Output:
Even Numbers from 1 to 10:
2 4 6 8 10```

## Program to print EVEN numbers from 1 to N using while loop

``````#include <stdio.h>

int main()
{
//loop counter declaration
int number;
//variable to store limit /N
int n;

//from where we want to print the numbers
number=1;

//input value of N
printf("Enter the value of N: ");
scanf("%d",&n);

//print statement
printf("Even Numbers from 1 to %d:\n",n);

//while loop, that will print numbers
while(number<=n)
{
//Here is the condition to check EVEN number
if(number%2==0)
printf("%d ",number);

// increasing loop counter by 1
number++;
}

return 0;
}``````

Output

```Run(1)
Enter the value of N: 10
Even Numbers from 1 to 10:
2 4 6 8 10

Run(2)
Enter the value of N: 100
Even Numbers from 1 to 100:
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
32 34 36 38 40 42 44 46 48 50 52 54 56 58
60 62 64 66 68 70 72 74 76 78 80 82 84 86
88 90 92 94 96 98 100
```

### Another way to print EVEN numbers from 1 to N

Since, we know that EVEN numbers starts from 2 and EVEN numbers are those numbers which are divisible by 2. So, we can run a loop from 2 to N by increasing the value of loop counter by 2.

Consider the given code...

``````//initialising the number by 2
number=2;
//print statement
printf("Even Numbers from 1 to %d:\n",n);

//while loop, that will print numbers
while(number<=n)
{
//print the number
printf("%d ",number);
//increase the value of number by 2
number+=2;
}``````