Logic to implement

1. Find the modulus of number dividing by 2 (as we know that EVEN number’s modulus is 0 and ODD number’s modulus is 1).
2. Check the case values with 0 and 1.
3. In the case value 0, number will be EVEN and case value 1, number will be ODD.

Check EVEN or ODD program using switch

/*C program to check whether number is EVEN or ODD using switch.*/
 
#include <stdio.h>
 
int main()
{
    int number;
     
    printf("Enter a positive integer number: ");
    scanf("%d",&number);
     
    switch(number%2) //this will return either 0 or 1
    {
        case 0:
            printf("%d is an EVEN number.\n",number);
            break;
        case 1:
            printf("%d is an ODD number.\n",number);
            break;
    }
     
    return 0;
}

Output

First run:
Enter a positive integer number: 10 
10 is an EVEN number. 

Second run:
Enter a positive integer number: 11 
11 is an ODD number.