Q:

# C program to design calculator with basic operations using switch

This program will read two integer numbers and an operator like +,-,*,/,% and then print the result according to given operator, it is a complete calculator program on basic arithmetic operators using switch statement in c programming language.

need an explanation for this answer? contact us directly to get an explanation for this answer

## Calculator program with Basic operations using switch

``````/*C program to design calculator with basic operations using switch.*/

#include <stdio.h>

int main()
{
int num1,num2;
float result;
char ch;    //to store operator choice

printf("Enter first number: ");
scanf("%d",&num1);
printf("Enter second number: ");
scanf("%d",&num2);

printf("Choose operation to perform (+,-,*,/,%): ");
scanf(" %c",&ch);

result=0;
switch(ch)
{
case '+':
result=num1+num2;
break;

case '-':
result=num1-num2;
break;

case '*':
result=num1*num2;
break;

case '/':
result=(float)num1/(float)num2;
break;

case '%':
result=num1%num2;
break;
default:
printf("Invalid operation.\n");
}

printf("Result: %d %c %d = %f\n",num1,ch,num2,result);
return 0;
}``````

Output

```    First run:
Enter first number: 10
Enter second number: 20
Choose operation to perform (+,-,*,/,%): +
Result: 10 + 20 = 30.000000

Second run:
Enter first number: 10
Enter second number: 3
Choose operation to perform (+,-,*,/,%): /
Result: 10 / 3 = 3.333333

Third run:
Enter first number: 10
Enter second number: 3
Choose operation to perform (+,-,*,/,%): >
Invalid operation.
Result: 10 > 3 = 0.000000 ```

need an explanation for this answer? contact us directly to get an explanation for this answer