Q:

C++ Program To Find Sum Of The Given Series x+x^2/2+x^3/3+x^4/4+ . . . . x^n/n

0

Logic :-

 This is very simple series just take a input a value of 'X' and numbers of terms and calculate the sum .at the end print the sum the logic is given below .

 
for(i=1;i<=n;++i)
{
sum+=pow(x,i)/i;
}

All Answers

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#include<iostream>
#include<math.h>
using namespace std;
int main()
{
 int i,n;
 float x,sum=0;

 cout<<"\nx+x^2/2+x^3/3+…..+x^n/n\n";
 cout<<"\nEnter value of x and n :\n";
 cin>>x>>n;

 for(i=1;i<=n;++i)
 {
  sum+=pow(x,i)/i;
 }
 cout<<"\nSum Is = "<<sum<<endl;
 return 0;
}

 

Output:

x+x^2/2+x^3/3+…..+x^n/n

Enter value of x and n :

2

5

Sum Is = 17.0667

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