C++ Program to Find Power of a Number using for loop

The program below takes two integers from the user (a base number and Power to base) and calculates the power.

For example :: In case of 25

• 2 is the base number
• 5 is the power to the base number
• And, the power of number is equal to 2*2*2*2*2

Here is source code of the C++ Program to Find Power of a Number using for loop. The C++ program is successfully compiled and run(on Codeblocks) on a Windows system. The program output is also shown in below.

SOURCE CODE : 

/*  C++ Program to Find Power of a Number using for loop  */

#include<iostream>
using namespace std;

int main()
{
   int b,p,i,pow=1;
   cout<<"Enter base of a number :: ";
   cin>>b;
   cout<<"\nEnter power to a base [ "<<b<<" ] :: ";
   cin>>p;

   for(i=p;i>0;i--)
   {
        pow=pow*b;
   }
   cout<<"\nPower of a Number [ "<<b<<" ^ "<<p<<" ] :: "<<pow<<"\n";

  return 0;
  }

Output : :

/*  C++ Program to Find Power of a Number using for loop  */

Enter base of a number :: 2

Enter power to a base [ 2 ] :: 6

Power of a Number [ 2 ^ 6 ] :: 64

Process returned 0

Above is the source code for C++ Program to Find Power of a Number using for loop which is successfully compiled and run on Windows System.The Output of the program is shown above .