Q:

C++ Program To Find Sum of Even Positive / Even Negative / Odd Positive / Odd Negative of An Array

belongs to collection: Array Programs In C++ Programming

ghaidaib
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2022-05-14
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Logic:- 
Here we need to solve two problems one in even-odd and second in positive-negative and according to the problem, As we know that if the number is divided by 2 then number is even and if not then the number is odd. we can solve before proceeding even-odd, and if the number is greater than zero then the number is positive and if the number is less then zero then the number is negative.
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ghaidaib
2022-05-14
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#include<iostream>
using namespace std;
int main()
{
  int a[100],i,n,k=0,rem=0,sum=0,odde=0,oddn=0;
  
 cout<<"Enter The Size of Array\n";
  cin>>n;
  
 cout<<"Enter The Array Element\n";
  for(i=0;i<n;i++)
  {
   cin>>a[i];
  }

  for(i=0;i<n;i++)
  {
  if(a[i]>=0)
  {
   if(a[i]%2==0)
   sum=sum+a[i];
   else
   rem=rem+a[i];
  } 
  else
  {
   if(a[i]%2==0)
   odde=odde+a[i];
   else
   oddn=oddn+a[i];
  } 
  }
  cout<<sum<<" Is Sum of Even-Positive\n";
  cout<<rem<<" Is Sum of Odd-Positive\n";
  cout<<odde<<" Is Sum of Even-Negative\n";
  cout<<oddn<<" Is Sum of Odd-Negative\n";
  return 0;
}

 

Output:

Enter The Size of Array

6

Enter The Array Element

1

-2

-3

4

-5

6

10 Is Sum of Even-Positive

1 Is Sum of Odd-Positive

-2 Is Sum of Even-Negative

-8 Is Sum of Odd-Negative

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