Java program to print the following pattern on the console

belongs to collection: Java Pattern programs

robaa

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2022-11-12

206

Algorithm:

STEP 1: START
STEP 2: SET coe=1, rows= 6.
STEP 3: SET i=0. REPEAT STEP 4 to STEP 11 UNTIL i<rows.< li=""></rows.<>
STEP 4: SET space = 1. REPEAT STEP 5 and STEP 6 UNTIL space<(rows ?i)
STEP 5: PRINT ""
STEP 6: ++space
STEP 7: SET j=0. REPEAT STEP 8 to STEP 9 UNTIL j<=i .
STEP 8: IF(j==0||i==0)
SET coe=1
ELSE
SET coe=coe*(i-j+1) /j
PRINT coe
STEP 9: SET j = j+1
STEP 10: PRINT new line.
STEP 11: SET i=i+1
STEP 12: END

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All Answers

robaa

2022-11-12

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Program:

class pattern  
  
   public static void main(String[] args)  
   {  
       int coe=1,rows = 6;  
    for(int i = 0; i < rows; i++) {  
           for(int space = 1; space < rows - i; ++space) {  
               System.out.print("  ");  
           }  
  
           for(int j = 0; j <= i; j++) {  
               if (j == 0 || i == 0)  
                   coe = 1;  
               else  
                   coe = coe * (i - j + 1) / j;  
  
               System.out.printf("%4d", coe);  
           }  
     System.out.println();  
       }  
   }  
  }

Output: