Q:

Python program to search an element in a Circular Linked List

belongs to collection: Python Circular Linked List Programs

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In this program, we create a circular linked list and search a node in the list.

9->5->2->7->3  

Consider, above example. Suppose we need to search for node 5. To solve this problem, we will iterate through the list and compare each node with 5. If a match is found, we will set the flag to true and prints out the position of the node 5. In this example, node 5 is present at position 2.

ALGORITHM:

  1. Define a Node class which represents a node in the list. It has two properties data and next which will point to the next node.
  2. Define another class for creating a circular linked list, and it has two nodes: head and tail.
  3. search() will search for a node in the list:
  • Variable i will keep track of the position of the searched node.
  • The variable flag will store boolean value false.
  • Current will point to head node.
  • Iterate through the loop by incrementing current to current.next and i to i + 1.
  • Compare each node's data with the searched node if a match is found, set the flag to true.
  • If the flag is true, prints the position of the searched node.
  • Else, print the message "Element is not present in the list".

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PROGRAM:

#Represents the node of list.    
class Node:    
    def __init__(self,data):    
        self.data = data;    
        self.next = None;    
     
class CreateList:    
    #Declaring head and tail pointer as null.    
    def __init__(self):    
        self.head = Node(None);    
        self.tail = Node(None);    
        self.head.next = self.tail;    
        self.tail.next = self.head;    
        
    #This function will add the new node at the end of the list.    
    def add(self,data):    
        newNode = Node(data);    
        #Checks if the list is empty.    
        if self.head.data is None:    
            #If list is empty, both head and tail would point to new node.    
            self.head = newNode;    
            self.tail = newNode;    
            newNode.next = self.head;    
        else:    
            #tail will point to new node.    
            self.tail.next = newNode;    
            #New node will become new tail.    
            self.tail = newNode;    
            #Since, it is circular linked list tail will point to head.    
            self.tail.next = self.head;    
                
    #Searches for a node in the list    
    def search(self,element):    
        current = self.head;    
        i = 1;    
        flag = False;    
        #Checks whether list is empty    
        if(self.head == None):    
            print("List is empty");    
        else:    
            while(True):     
                #Compares element to be found with each node present in the list    
                if(current.data ==  element):    
                    flag = True;    
                    break;    
                current = current.next;    
                i = i + 1;    
                if(current == self.head):    
                    break;    
            if(flag):    
                print("Element is present in the list at the position :  " + str(i));    
            else:    
                print("Element is not present in the list");    
     
class CircularLinkedList:    
    cl = CreateList();    
    #Adds data to the list    
    cl.add(1);    
    cl.add(2);    
    cl.add(3);    
    cl.add(4);    
    #Search for node 2 in the list    
    cl.search(2);    
    #Search for node in the list    
    cl.search(7);    

 

Output:

Element is present in the list at the position: 2
Element is not present in the list

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