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Python Program to Check Leap Year

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robaa
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2022-11-06
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Leap Year:

A year is called a leap year if it contains an additional day which makes the number of the days in that year is 366. This additional day is added in February which makes it 29 days long.

A leap year occurred once every 4 years.

How to determine if a year is a leap year?

You should follow the following steps to determine whether a year is a leap year or not.

  1. If a year is evenly divisible by 4 means having no remainder then go to next step. If it is not divisible by 4. It is not a leap year. For example: 1997 is not a leap year.
  2. If a year is divisible by 4, but not by 100. For example: 2012, it is a leap year. If a year is divisible by both 4 and 100, go to next step.
  3. If a year is divisible by 100, but not by 400. For example: 1900, then it is not a leap year. If a year is divisible by both, then it is a leap year. So 2000 is a leap year.
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robaa
2022-11-06
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# Default function to implement conditions to check leap year  
def CheckLeap(Year):  
  # Checking if the given year is leap year  
  if((Year % 400 == 0) or  
     (Year % 100 != 0) and  
     (Year % 4 == 0)):   
    print("Given Year is a leap Year");  
  # Else it is not a leap year  
  else:  
    print ("Given Year is not a leap Year")  
# Taking an input year from user  
Year = int(input("Enter the number: "))  
# Printing result  
CheckLeap(Year)

Output:

Enter the number: 1700
Given year is not a leap Year

Explanation:

We have implemented all the three mandatory conditions (that we listed above) in the program by using the 'and' and 'or' keyword inside the if else condition. After getting input from the user, the program first will go to the input part and check if the given year is a leap year. If the condition satisfies, the program will print 'Leap Year'; else program will print 'Not a leap year.'

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