Q:

Rust program to check a number contain the alternative pattern of bits

belongs to collection: Rust Basic Programs

YasminRadwan26
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2022-07-16
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Here, we will create a 16-bit integer number and then we will check the number contains the alternate pattern of bits or not.

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YasminRadwan26
2022-07-16
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Program/Source Code:

The source code to check a number contain the alternative pattern of bits is given below. The given program is compiled and executed successfully.

// Rust program to check a number contain 
// the alternative pattern of bits

fn main() {
    let mut num:i16 = 10;
    let mut val:i16 = 0;
    let mut cnt:i16 = 0;
    let mut flg:i16 = 0;
    
    let mut tmp:i16 = 0;
    let mut tmp1:i16 = 0;
    let mut tmp2:i16 = 0;
    
    println!("Decimal Number: {}",num);
    println!("Binary Number: {:#02b}",num);
    
    tmp = num;
    while tmp>0 {
        cnt=cnt+1;
        tmp = tmp >> 1;
    }
    
    while val< cnt-1
    {
        tmp1 = (num >> val) & 1;
        tmp2 = (num >> (val + 2)) & 1;
        
        if tmp1== tmp2
        {
            val = val + 1;
        }
        else 
        {
            flg=1;
            break;
        }
    }
 
    if flg==1
    {
        println!("Alternate BIT pattern does not exist");
    }
    else
    {
        println!("Alternate BIT pattern exists");
    }
}

Output:

Decimal Number: 10
Binary Number: 0b1010
Alternate BIT pattern exists

Explanation:

Here, we created an integer variable num with an initial value of 10. Then we checked the given number contains the alternat pattern of bits and printed the appropriate message.

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