Detect if two integers have opposite signs?

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YasminRadwan26

2022-06-24

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Answer:

The two integers have different signs if their MSB (bit) is different. Using the EX-OR operator, we can check the sign of the integers.

We know that for the same input EX-OR produces the low output and for the different input it produces the high output.

E.g.

BIT1	BIT2	BIT1 ^ BIT2
1	1	0
0	0	0
1	0	1
0	1	1

Let the given integers are “a” and “b”. The EX-OR of sign bit (MSB) of “a” and “b” will be 1 if the MSB of “a” and “b” is different. In other words, we can say, EX-OR of “a” and “b” will be negative if “a” and “b” have the opposite signs.

#include<stdbool.h>
#include<stdio.h>
bool CheckOppositeSign(int a, int b)
{
    bool bRetValue = 0;
    bRetValue = ((a ^ b) < 0); // 1 if a and b have opposite signs
    return bRetValue;
}
int main()
{
    int a = 0,b=0;
    bool bRetValue;
    //ENTER THE VALUE OF a & b
    printf("Enter the Value of a = ");
    scanf("%d",&a);
    printf("\nEnter the Value of b = ");
    scanf("%d",&b);
    bRetValue = CheckOppositeSign(a, b); // check signs of a & b
    if (true == bRetValue)
    {
        printf ("\nIntegers have the opposite sign\n\n");
    }
    else
    {
        printf ("\nInteger have the same sign\n\n");
    }
    return 0;
}

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Detect if two integers have opposite signs?

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