Java program to handle a generated exception

Java programming, exam questions, Java programming exam-questions,

All Answers

mahmoud2506

2022-05-07

need an explanation for this answer? contact us directly to get an explanation for this answer

In this program, we will handle an exception (run-time error) using try, catch block. The code that may generate an exception should be written in the "try" block, and the "catch" block is used to handle the exception and prevent program crashes.

Program/Source Code:

The source code to handle a generated exception is given below. The given program is compiled and executed successfully.

// Java program to handle a generated exception

public class Main {
  public static void main(String[] args) {
    try {
      int a = 10, b = 0, c = 0;

      c = a / b;

      System.out.println("Division is: " + c);
    } catch (Exception e) {
      System.out.println("Exception generated");
    }

    System.out.println("Program Finished");
  }
}

Output:

Exception generated
Program Finished

Explanation:

In the above program, we created a class Main. The Main class contains a main() method. The main() method is the entry point for the program.

Here, we created "try" and "catch" blocks. In the "try" block, divide by zero exception gets generated but we handled exception using the "catch" block and prevent from the program crashing.

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)

Java program to handle a generated exception

Java program to handle a generated exception

All Answers

Java Exception Handling Programs

This question belongs to these collections

Similar questions

need a help?

find thousands of online teachers now