Java program to demonstrate the protected access specifier

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mahmoud2506

2022-05-07

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Program/Source Code:

The source code to demonstrate the protected access specifier is given below. The given program is compiled and executed successfully.

// Java program to demonstrate the 
// protected access specifier

class A {
  protected void MethodA() {
    System.out.println("MethodA called");
  }
}

class B extends A {
  protected void MethodB() {
    System.out.println("MethodB called");
  }
}

class C extends B {
  protected void MethodC() {
    System.out.println("MethodC called");
  }
}

public class Main {
  public static void main(String[] args) {
    C obj = new C();

    obj.MethodA();
    obj.MethodB();
    obj.MethodC();
  }
}

Output:

MethodA called
MethodB called
MethodC called

Explanation:

In the above program, we created 4 classes A, B, C, and Main(). Here, we implemented multi-level inheritance and created methods using protected access specifiers.

The Main class contains a method main(). The main() method is the entry point for the program, here we created the object of class C and called methods of all inherited classes, and printed the messages.

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Java program to demonstrate the protected access specifier

Java program to demonstrate the protected access specifier

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