In this program, we will create 3 methods with the same name but all methods have a different number of arguments to calculate the sum of given arguments.
Program/Source Code:
The source code to implement method overloading based on the number of arguments is given below. The given program is compiled and executed successfully.
// Java program to implement method overloading
// based on the number of arguments
public class Main {
static int sum(int a, int b) {
int s = 0;
s = a + b;
return s;
}
static int sum(int a, int b, int c) {
int s = 0;
s = a + b + c;
return s;
}
static int sum(int a, int b, int c, int d) {
int s = 0;
s = a + b + c + d;
return s;
}
public static void main(String[] args) {
int result = 0;
result = sum(10, 20);
System.out.println("Sum : " + result);
result = sum(10, 20, 30);
System.out.println("Sum : " + result);
result = sum(10, 20, 30, 40);
System.out.println("Sum : " + result);
}
}
Output:
Sum : 30
Sum : 60
Sum : 100
Explanation:
In the above program, we created a Main class that contains a method main() and 3 overloaded method sum() to calculate the addition of a specified different number of arguments.
The main() method is the entry point for the program, here we called overloaded methods and printed the result.
In this program, we will create 3 methods with the same name but all methods have a different number of arguments to calculate the sum of given arguments.
Program/Source Code:
The source code to implement method overloading based on the number of arguments is given below. The given program is compiled and executed successfully.
Output:
Explanation:
In the above program, we created a Main class that contains a method main() and 3 overloaded method sum() to calculate the addition of a specified different number of arguments.
The main() method is the entry point for the program, here we called overloaded methods and printed the result.
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