The number which is equal to the sum of its digit's cube known as "Armstrong Number", in this Java program, we are going to read an integer number and check whether entered number is Armstrong or not.
Let suppose there is a number 153 (it's an Armstrong number), it is equal to the sum of each it's digit's cube (1*1*1 + 5*5*5 + 3*3*3 = 1+125+27 = 153).
import java.util.Scanner;
public class ArmStrongNumber {
static boolean isArmStrongNo(int number){
boolean isArmNumber=false;
int sum=0;
int tempNum= number;
while(tempNum>0){
int r =tempNum%10;
sum =sum+(r*r*r);
tempNum =tempNum/10;
}
if(sum==number){
isArmNumber =true;
}
return isArmNumber;
}
public static void main(String[] arg){
Scanner sc = new Scanner(System.in);
System.out.println("Enter Number : ");
int num = sc.nextInt();
if(isArmStrongNo(num)){
System.out.println(num+" is an ArmStrong Number");
}
else{
System.out.println(num+" is not an ArmStrong Number");
}
}
}
Program to check Armstrong number in Java
Output