Q:

The expected workload of generating a collision is of the order of ____________ executions of Whirlpool

0

The expected workload of generating a collision is of the order of ____________ executions of Whirlpool.


  1. 2^(n/2)
  2. 2^(n-1)
  3. 2^(n)
  4. 2^(2n)

All Answers

need an explanation for this answer? contact us directly to get an explanation for this answer

 (a).2^(n/2)

need an explanation for this answer? contact us directly to get an explanation for this answer

total answers (1)

CRYPTOGRAPHY AND NETWORK SECURITY - MESSAGE AUTHENTICATION CODES AND KEY MANAGEMENT MCQ

Similar questions


need a help?


find thousands of online teachers now
Given a message, the expected workload of finding ... >>
<< Which of the following is not true for whirlpool h...