C++ code to extract and print digits of a number in reverse order

#include <iostream>

using namespace std;

int main()
{
    int num;
    int a = 0;

    cout << "Enter a number: ";
    cin >> num;
    cout << "\n";

    for (int i = 1; num > 0; i++) {
        a = num % 10;
        cout << a;
        num = num / 10;
    }

    return 0;
}

Output

Enter a number: 123456

654321

Here we are first using a loop with condition num>0, and the last digit of the number is taken out by using simple % operator after that, the remainder term is subtracted from the num. Then number num is reduced to its 1/10th so that the last digit can be truncated.

The cycle repeats and prints the reverse of the number num.