Q:

Python program to perform cross pairing in tuple list

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mahmoud2506
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2022-05-23
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Example:

tuple = ("python", "includehelp", 43, 54.23)

List is a sequence data type. It is mutable as its values in the list can be modified. It is a collection of an ordered set of values enclosed in square brackets [].

Example:

list = [3 ,1,  5, 7]

We have two lists with each element a tuple and we need to perform cross pairing i.e. we need to create a tuple with second elements of tuples whose first elements are the same.

Here is an example for a better understanding of the problem,

Input:
tupList1 = [(1, 8), (9, 6), (0, 8), (4,5)] 
tupList2 = [(7, 8), (2, 5), (3, 6), (4,7)]

Output:
(5, 7)

Explanation: Here, only the tuples (4,5) and (4,7) have common first elements. So, cross pairing will consider both of them only.

 

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All Answers

mahmoud2506
2022-05-23
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To solve this problem, we will be traversing the list and then checking for each tuple if there exists a tuple in another list that has the same first elements as this tuple. If yes, we will make a tuple with the second values of both the tuples and store them in a list.

For performing this task in the python programming language, we have more than one way as python has many built-in methods to reduce our efforts in tasks.

Method 1:

One way to solve the problem is by using list comprehension along with comparison using condition statements to create a new tuple that will have a second element of the tuple whose first element is the same.

# Python program to perform 
# Cross Pairing in Tuple List

# Creating and printing tuple list  
myList1 = [(1, 8), (9, 6), (0, 8), (4,5)]
myList2 = [(1, 3), (2, 1), (9, 7), (2, 17)]
print("Tuples of list 1 are " + str(myList1))
print("Tuples of list 2 are " + str(myList2))

# Performing cross Pairing in Tuple list 
crossTupleList = [(sub1[1], sub2[1]) for sub2 in myList2 for sub1 in myList1 if sub1[0] == sub2[0]]

# Printing crossed Tuple list 
print("Resultant Tuple list : " + str(crossTupleList))

Output:

Tuples of list 1 are [(1, 8), (9, 6), (0, 8), (4, 5)]
Tuples of list 2 are [(1, 3), (2, 1), (9, 7), (2, 17)]
Resultant Tuple list : [(8, 3), (6, 7)]

Method 2:

An alternate method to solve the problem is by using the zip() method with the condition of the first element's equality along with list comprehension.

# Python program to perform
# Cross Pairing in Tuple List

# Creating and printing tuple list  
myList1 = [(1, 8), (9, 6), (0, 8), (4,5)]
myList2 = [(1, 3), (2, 1), (9, 7), (2, 17)]
print("Tuples of list 1 are " + str(myList1))
print("Tuples of list 2 are " + str(myList2))

# Performing cross Pairing in Tuple list 
crossTupleList = [(val1[1], val2[1]) for val1, val2 in zip(myList1, myList2) if val1[0] == val2[0]]

# Printing crossed Tuple list 
print("Resultant Tuple list : " + str(crossTupleList))

Output:

Tuples of list 1 are [(1, 8), (9, 6), (0, 8), (4, 5)]
Tuples of list 2 are [(1, 3), (2, 1), (9, 7), (2, 17)]
Resultant Tuple list : [(8, 3)]

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