#include <stdio.h>
int main(void) {
int choice = 2;
switch(choice);
{
case 1:
printf("Case 1\n");
break;
case 2:
printf("Case 2\n");
break;
case 3:
printf("Case 3\n");
break;
case 4:
printf("Case 4\n");
break;
default:
printf("Case default\n");
}
return 0;
}
Output
prog.c: In function ‘main’:
prog.c:9:6: error: case label not within a switch statement
case 1:
^~~~
prog.c:11:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:12:6: error: case label not within a switch statement
case 2:
^~~~
prog.c:14:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:15:6: error: case label not within a switch statement
case 3:
^~~~
prog.c:17:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:18:6: error: case label not within a switch statement
case 4:
^~~~
prog.c:20:10: error: break statement not within loop or switch
break;
^~~~~
prog.c:21:6: error: ‘default’ label not within a switch statement
default:
^~~~~~~
How to fix?
See the statement switch(choice); it is terminated by semicolon (;) – it must not be terminated. To fix this error, remove semicolon after this statement.
Correct code:
#include <stdio.h>
int main(void) {
int choice = 2;
switch(choice)
{
case 1:
printf("Case 1\n");
break;
case 2:
printf("Case 2\n");
break;
case 3:
printf("Case 3\n");
break;
case 4:
printf("Case 4\n");
break;
default:
printf("Case default\n");
}
return 0;
}
Example:
Output
How to fix?
See the statement switch(choice); it is terminated by semicolon (;) – it must not be terminated. To fix this error, remove semicolon after this statement.
Correct code:
Output
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