Executing more than one case block in C – is not a syntax error, it's a logical error and it occurs when you miss to place break statement in the case block.
Example:
#include <stdio.h> int main(void) { int choice = 2; switch(choice){ case 1: printf("Case 1\n"); case 2: printf("Case 2\n"); case 3: printf("Case 3\n"); case 4: printf("Case 4\n"); default: printf("Case default\n"); } return 0; }
Output
Case 2 Case 3 Case 4 Case default
How to fix?
Use break with each case block.
Correct code:
#include <stdio.h> int main(void) { int choice = 2; switch(choice){ case 1: printf("Case 1\n"); break; case 2: printf("Case 2\n"); break; case 3: printf("Case 3\n"); break; case 4: printf("Case 4\n"); break; default: printf("Case default\n"); } return 0; }
Case 2
total answers (1)
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Example:
Output
How to fix?
Use break with each case block.
Correct code:
Output
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