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Print list in reverse order using a loop using python programming

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YasminRadwan26
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2022-05-03
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Print list in reverse order using a loop

Given:

list1 = [10, 20, 30, 40, 50]

Expected output:

50
40
30
20
10
Python programming,
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YasminRadwan26
2022-05-03
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Hint:

Approach 1: Use the built-in function reversed() to reverse the list

Approach 2: Use for loop and the len() function

  • Get the size of a list using the len(list1) function
  • Use for loop and reverse range() to iterate index number in reverse order starting from length-1 to 0. In each iteration, i will be reduced by 1
  • In each iteration, print list item using list1[i]. i is the current value if the index

Solution1:Using a reversed() function and for loop

list1 = [10, 20, 30, 40, 50]
# reverse list
new_list = reversed(list1)
# iterate reversed list
for item in new_list:
    print(item)

Solution2:Using for loop and the len() function

list1 = [10, 20, 30, 40, 50]
# get list size
# len(list1) -1: because index start with 0
# iterate list in reverse order
# star from last item to first
size = len(list1) - 1
for i in range(size, -1, -1):
    print(list1[i])

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