Write a program in C++ to convert hexadecimal number to binary number

#include<iostream>
#include<stdlib.h>
#include<math.h>
using namespace std; 
 
unsigned long Hex_To_Dec(char hex[]) 
{
  char *hexstring;
  int length = 0;
  const int hexbase = 16;     
  unsigned long dnum = 0;
  int i;
  for (hexstring = hex; *hexstring != '\0'; hexstring++) 
  {
      length++;
    }
  hexstring = hex;
  for (i = 0; *hexstring != '\0' && i < length; i++, hexstring++) 
  {
      if (*hexstring >= 48 && *hexstring <= 57) 
	  {  
          dnum += (((int)(*hexstring)) - 48) * pow(hexbase, length - i - 1);
        }
      else if ((*hexstring >= 65 && *hexstring <= 70))  
	  {  
          dnum += (((int)(*hexstring)) - 55) * pow(hexbase, length - i - 1);
        }
      else if (*hexstring >= 97 && *hexstring <= 102) 
	  {  
          dnum += (((int)(*hexstring)) - 87) * pow(hexbase, length - i - 1);
        }
      else {
          cout<<" The given hexadecimal number is invalid. \n";
        }
    }
  return dnum;
}

int  main() 
{
  unsigned long dnum;
  char hex[9];
          int dec_num, rem=1, m, n;
        int bin_num[100],quot;
	dec_num=0;
	cout << "\n\n Convert any hexadecimal number to binary number:\n";
	cout << "------------------------------------------------------\n";
	cout << " Input any 32-bit Hexadecimal Number: ";  
    cin>>hex;
    dnum = Hex_To_Dec(hex);
    quot = dnum;
    cout<<" The equivalent binary number is: ";
       
        while(quot != 0)
        {
            bin_num[m++] = quot % 2;
            quot = quot/2;
        }
        for(n=m-1; n>=0; n--)
        {
            dec_num=(dec_num*10)+bin_num[n];
        }
		cout<<dec_num<<endl;
		cout<<endl;
}