Write a C++ program to count the number of two 5's are next to each other in an array of integers. Also count the situation where the second 5 is actually a 6

#include <iostream>

using namespace std;

int test(int numbers[], int arr_length)
        {
            int ctr = 0;
            for (int i = 0; i < arr_length; i++)
            {
                if ((numbers[i]==5 && (numbers[i + 1]==5 )) || ( numbers[i]==5 && (numbers[i + 1]==6))) ctr++;
            }
            return ctr;
        }
        
int main() 
 {
  int arr_length;	
  int nums1[] = {5, 5, 2};	
  arr_length = sizeof(nums1) / sizeof(nums1[0]);
  cout << test(nums1, arr_length) << endl; 
  int nums2[] = {5, 5, 2, 5, 5};	
  arr_length = sizeof(nums2) / sizeof(nums2[0]);
  cout << test(nums2, arr_length) << endl;
  int nums3[] = {5, 6, 2, 9};	
  arr_length = sizeof(nums3) / sizeof(nums3[0]);
  cout << test(nums3, arr_length) << endl;
  return 0;   
}