Write a C++ program to check which number nearest to the value 100 among two given integers. Return 0 if the two numbers are equal

#include <iostream>
using namespace std;

int test(int x, int y)
        {
            const int n = 100;
            int val = abs(x - n);
            int val2 = abs(y - n);

            return val == val2 ? 0 : (val < val2 ? x : y);
        }
        
int main() 
 {
  cout << test(78, 95) << endl;  
  cout << test(95, 95) << endl;  
  cout << test(99, 70) << endl;  
  return 0;    
}