Python | Count total number of bits in a number

Program:

# count total number of bits in a number 

# declare a number
num = 61

# use bin () method to get the binary value of a number 
# print binary value output will be 0b111101
print "binary value of {0} is: {1}".format (num, bin(num))

# store the length of the binary number
length = len(bin(num))

# since binary value contains 0b as prefix
# so to get exact length total number of bits
# subtract 2 from the length
length -=2

# print length
print "total number of bits: ", length

Output

binary value of 61 is: 0b111101
total number of bits:  6

By defining function

In the below program, we used len(bin(n)[2:]), it will return total length of the binary value after 2 characters.

Let’s understand

    a=61
    = len(bin(a)[2:])		# bin(a) is '0b111101'
    = len('0b111101'[2:])
    = len ('111101')
    = 6

Program:

# count total number of bits in a number
# function to get total bits
# function will return total nember of bits
def totalBits(n):
	return len(bin(n)[2: ])

#main code 
a = 61 
b = 12

print "Total bits in {0} = {1} ".format(a,totalBits(a))
print "Total bits in {0} = {1} ".format(b,totalBits(b))

Output

Total bits in 61 = 6 
Total bits in 12 = 4