Q:

Python | Design a simple calculator using if elif (just like switch case)

0

Given two numbers and we have to design a calculator type application that will perform add, subtract, multiply and divide operations using Python.

Example:

    Message:
    Calculator 
    1.Add
    2.Substract
    3.Multiply
    4.Divide

    Input:
    Enter Choice(1-4): 3
    Enter A:10
    Enter B:20

    Output:
    Product =  200

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Program:

# menus
print("Calculator")
print("1.Add")
print("2.Substract")
print("3.Multiply")
print("4.Divide")

# input choice
ch=int(input("Enter Choice(1-4): "))

if ch==1:
    a=int(input("Enter A:"))
    b=int(input("Enter B:"))
    c=a+b
    print("Sum = ",c)
elif ch==2:
    a=int(input("Enter A:"))
    b=int(input("Enter B:"))
    c=a-b
    print("Difference = ",c)
elif  ch==3:
    a=int(input("Enter A:"))
    b=int(input("Enter B:"))
    c=a*b
    print("Product = ",c)
elif ch==4:
    a=int(input("Enter A:"))
    b=int(input("Enter B:"))
    c=a/b
    print("Quotient = ",c)
else:
    print("Invalid Choice")

Output

Calculator
1.Add
2.Substract
3.Multiply
4.Divide
Enter Choice(1-4): 3
Enter A:10
Enter B:20
Product =  200

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