Python program to check the given year is a leap year or not

1) By using the calendar module

Before going to solve the problem, initially, we learn a little bit about the calendar module. Calendar module is inbuilt in Python which provides us various functions to solve the problem related to date, month and year.

Program:

# importing the module
import calendar

# input the year 
year=int(input('Enter the value of year: '))
leap_year=calendar.isleap(year)

# checking leap year
if leap_year: # to check condition
    print('The given year is a leap year.')
else:
    print('The given year is a non-leap year.')

Output

RUN 1:
Enter the value of year: 2020
The given year is a leap year.

RUN 2:
Enter the value of year: 2021
The given year is a non-leap year.

2) By simply checking the leap year condition

As we know the condition to check the given year is a leap year or not. So, here we will implement the condition and try to write the Python program.

Program:

# input the year
y=int(input('Enter the value of year: '))

# To check for non century year
if y%400==0 or y%4==0 and y%100!=0: 
    print('The given year is a leap year.')
else:
    print('The given year is a non-leap year.')

Output

RUN 1:
Enter the value of year: 2020
The given year is a leap year.

RUN 2:
Enter the value of year: 2000
The given year is a leap year.