C++ Program To Find Sum Of Given Series 1^2+3^2+5^2+ . . . . n^2

ghaidaib

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2022-05-16

328

Logic :-

In This series loop initialize with zero and increase by 2 cause we have to find the sum of the power of 2 odd number so first print odd number then power of 2 after that sum .

i+=2 ( increase by 2 )

i*i ( Power of 2 )

sum+=(i*i); ( sum of odd )

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ghaidaib

2022-05-16

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#include<iostream>
using namespace std;
int main()
{
 int n,i;
 long sum=0;

 cout<<"1^2+3^2+5^2+……+n^2\n\nEnter Value of N :\n";
 cin>>n;

 for(i=1;i<=n;i+=2)
 {
  sum+=(i*i);
 }

 cout<<"\nSum of given series is = "<<sum<<endl;
 return 0;
}

Output:

1^2+3^2+5^2+……+n^2

Enter Value of N :

Sum of given series is = 35

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C++ Program To Find Sum Of Given Series 1^2+3^2+5^2+ . . . . n^2

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