This is very simple series just take a input a value of 'X' and numbers of terms and calculate the sum .at the end print the sum the logic is given below .
#include<iostream>
#include<math.h>
using namespace std;
int main()
{
int i,n;
float x,sum=0;
cout<<"\nx+x^2/2+x^3/3+…..+x^n/n\n";
cout<<"\nEnter value of x and n :\n";
cin>>x>>n;
for(i=1;i<=n;++i)
{
sum+=pow(x,i)/i;
}
cout<<"\nSum Is = "<<sum<<endl;
return 0;
}
Output:
x+x^2/2+x^3/3+…..+x^n/n
Enter value of x and n :
2
5
Sum Is = 17.0667
need an explanation for this answer? contact us directly to get an explanation for this answer