Q:

# C++ Program To Check Even Or Odd Using Pointer

Logic:-

As we know that if the number is less than zero than a number is Negative or if a Number is Greater than Zero then the number is Positive or any case number is equal to zero. So in this problem we are comparing if the entered number by the user is less than zero or greater than zero or if the both condition fails than a number is definitely zero or we can say entered a number is zero.

### All Answers

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``````#include<iostream>
using namespace std;
int main()
{
int a;
int *p1;

p1=&a;

cout<<"Enter The Number You Want to Check \n\n";
cin>>a;

if(*p1>0)
{
cout<<"Number Is Possitive \n";
}
else if(*p1<0)
{
cout<<"Number Is Negative \n";
}
else
{
cout<<"Number Is Equal to Zero\n\n";
}
return 0;

}``````

Output:

Enter The Number You Want to Check

10

Number Is Possitive

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